1. Implement stack using queue
2. Merge two arrays and sort them in order as specified at runtime. The two arrays may share common entries between them, but the resultant array must not have duplicates.

Question

1. Implement stack using queue
2. Merge two arrays and sort them in order as specified at runtime. The two arrays may share common entries between them, but the resultant array must not have duplicates.

Michael · Accepted Answer

Dim integers = {1, 2, 3, "a"}
        Dim characters = {"a", "b", "c", 1}
        Dim newArray As New ArrayList
        Dim count As Integer = 0
        For Each item In characters
            If Not newArray.Contains(item) Then
                newArray.Add(item)
                newArray.Add(integers(count))
                count += 1
            End If
        Next

        For Each item In newArray
            MsgBox(item)
        Next

A · Answer

def isPresentN(element):
    for i in range(len(result1)):
        if (result1[i] == element):
            return True
    return False


def sortArray(inputA):
    for j in range(1,len(inputA)):
        for i in range(len(inputA)-j):
            if(inputA[i]>inputA[i+1]):
                temp = inputA[i]
                inputA[i] = inputA[i+1]
                inputA[i+1] = temp
    return inputA


def mergeArraySorted(inputArray1 , inputArray2):
    if (len(inputArray1)==0 and len(inputArray2)==0):
        return 'Both arrays are empty'
    elif (len(inputArray1)==0):
        return inputArray2
    elif (len(inputArray2)==0):
        return inputArray1
    print inputArray1,inputArray2
    first = 0
    second = 0
    while ((first < len(inputArray1)) and (second < len(inputArray2))):
        if ((isPresentN(inputArray1[first])==False) and (isPresentN(inputArray2[second])==False)):
            result1.append(inputArray1[first])
            result1.append(inputArray2[second])
            second = second + 1
            first = first + 1
        elif (isPresentN(inputArray1[first])):
            if isPresentN(inputArray2[second])==False:            
                result1.append(inputArray2[second])
                second = second + 1
        elif (isPresentN(inputArray2[second])):
            if isPresentN(inputArray1[first])==False:            
                result1.append(inputArray1[first])
                first = first + 1
        else:
            second = second + 1
            first = first + 1
    print result1
    return sortArray(result1)

Microsoft

Domanda di colloquio di Microsoft

Risposte di colloquio

Aziende seguite

Ricerche di lavoro