Domanda di colloquio di NBCUniversal
Code the FizzBuzz algorithm
Risposta di colloquio
Anonimo
2 ott 2018
Created an algorithm using if/else statements for returning either "fizz", "buzz" or "fizzbuzz".
Code the FizzBuzz algorithm
Anonimo
Created an algorithm using if/else statements for returning either "fizz", "buzz" or "fizzbuzz".