Describe how you would reverse a linked list.
Anonimo
I did two approaches on my answer. The first was recursive (i.e. it takes longer and uses more space the more nodes there are) and the second was linear, which ran in constant time. The prototypes looked like this: A) Recursive: Node * ReverseList(Node * current, Node *prev) { } B) Linear Node * ReverseList(Node * oldTopOfList) { }