Find the second maximum element in an unsorted array of integers, using single for loop.

Question

Nishant · Accepted Answer

#include

int main()
{
    int a[]={1,5,7,5,8,2,9,2,5,9};
    int max,max2;
    int i;
    max=max2=a[0];
    for(i=1;imax)
        {
            max2=max;
            max=a[i];
        }
        else if(a[i]max2)
        {
            max2=a[i];
        }
    }
    printf("%d",max2);

    return 0;
}

Spandan pathak · Answer

int main()
{
   int a[]={10,1,3,5,11,8,9,6};

int max,max2;

if(a[1]>a[0])
{
	max=a[1];
	max2=a[0];
}
else
{
	max=a[0];
	max2=a[1];
}

for(int i=2;imax2)
	{
		max2=a[i];
		if(max2>max)
		{
			max2=max;
			max=a[i];
		}
	}
}

cout<

Arpit Agrawal · Answer

#include
int main(){
int A[]={1,5,7,5,8,2,9,2,5,9};
int i,temp,max1=0,max2=0,n=(sizeof(A))/(sizeof(A[0]));
for(i=0;imax2){max2=A[i];}
}
printf("
1st Maximum Element:  %d",max1);
printf("
2st Maximum Element:  %d",max2);
return 0;}

Anurag Dhingra · Answer

#include 
using namespace std;

int main() {
	int arr[10];
	for(int i=0;i>arr[i];
	}
	
	int max,max2;max=max2=arr[0];
	for(int i=1;i=max) max=arr[i];
		
		if(arr[i]>=max2 && arr[i]!=max) max2=arr[i];
	}
	
	cout<

yuva · Answer

Solution One:
int min = 0;
int secondmin = 0;

if(array[0] < array[1]) {
  min = array[0];
  second_min = array[1];
} else {
  min = array[1];
  second_min = array[0];
}

for(i=3; i

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