Mainly two math problem:
-When can you start to work?
-Q1: 3-dimension rectangular solid, total surface 64 cm^2, total length of edges 40cm, find the length of longest diagonal.
-Q2: A coin, probability to get head is less than 0.5, the probability to flip it four times and get two heads and two tiles is 1/6. Find the probability to get a head in one flip.

Question

Mainly two math problem:
-When can you start to work?
-Q1: 3-dimension rectangular  solid, total surface 64 cm^2, total length of edges 40cm, find the length of longest diagonal.
-Q2: A coin, probability to get head is less than 0.5, the probability to flip it four times and get two heads and two tiles is 1/6. Find the probability to get a head in one flip.

me · Accepted Answer

u don't need a,b,c

2ab+2bc+2ac=64
 a+b+c=10
a^2 + b^2 + c^2 +2ab + 2ac+2bc = 100
d^2 = a^2 + b^2 +d^2 = 100 - 64 =36
d = 6

Anonimo · Answer

Q1=36
Q2=(3-sqrt(3))/6

b and c are not equal to 4. · Answer

You have 2 equations and 3 unknowns. If you assume b=c, then b and c are not 4. 
2*2*4+2*4*4+2*4*4=80

Jake · Answer

for Q2, you need to use the binomial coefficients for 4 events, where order doesnt matter: n!/k!(n-k)!
Then you know P(H)=1-P(T) and given 4 events, 36*(P(H)-P(H)^2)^2=1/6
You can solve this for P(H)=0.0734 and P(T)=0.9266

duan · Answer

2ab+2bc+2ac=64 a+b+c=10 a=2 b=4 c=4
x*x*(1-x)*(1-x)*6=1/6 X*(1-X)*6=1

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