obj * arr = new obj[10];
delete arr;

Question

obj * arr = new obj[10];
delete arr;

Anonimo · Accepted Answer

This ends up with segmentation fault on linux + gcc, which wasnt in the given choices.

Anonimo · Answer

And if it doesn't, it only calls the destructor of the first object in the array. In any case, it is UB (undefined behavior), so it can do anything the compiler decides to.

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