Domanda di colloquio di Murex
square root algorithm
Risposta di colloquio
Anonimo
18 feb 2014
double squareRoot = number/2; do { g=squareRoot; squareRoot = (g + (number/g))/2; System.out.println(" g =" +g + " squareRoot =" +squareRoot); } while((g-squareRoot)!=0);
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