Domanda di colloquio di IBM

swap two numbers without using temporary variable

Risposte di colloquio

Anonimo

15 mag 2011

b=a+b; a=b-a; b=b-a;

Anonimo

30 mag 2011

Sagar's answer is decent, but there might be problems if they consider overflow. Better is using xor: b = a XOR b a = a XOR b b = a XOR b