Domanda di colloquio di LinkedIn

Design LRU Cache

Risposte di colloquio

Anonimo

2 apr 2013

Use a priority queue. It can be reordered in terms of time accessed.

1

Anonimo

7 giu 2011

I tried to come out with a complicated solution, but they wanted the simplest one. A Hashmap and doubly linked list should satisfy them. Keep putting the recently accessed node on top of the queue and while inserting a new element, if its full, remove the last node in the queue.

Anonimo

23 feb 2012

why not use a minHeap?