1. Find the pivot.
2. Reverse the left side until the pivot.
3. Reverse the right side after pivot.
4. Reverser the whole array.
No need for extra storage and it's still O(n).
1
Anonimo
25 set 2010
Array is already sorted so
1) find the pivot point (use modified binary search)
2) since it is a array, block copy data using temporary buffer to reconstruct the sorted array