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      Colloqui di HugoSaveColloqui per Software Engineer(Internship) presso HugoSaveColloquio di HugoSave


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      Colloquio per Software Engineer(Internship)

      1 set 2024
      Candidato anonimo a colloquio
      Hyderabad
      Nessuna offerta
      Esperienza neutra
      Colloquio nella media

      Candidatura

      Ho presentato la mia candidatura tramite l'università. La procedura ha richiesto 2 giorni. Ho sostenuto un colloquio presso HugoSave (Hyderabad) nel mese di ago 2024

      Colloquio

      2 coding questions were asked each by a different person(for 30 min each). first question was easy and the second question was medium. just after that hr interview happened. common questions were asked in hr round like: what type of co-workers do you want? are you willing to relocate? what do you do apart from school?

      Domande di colloquio [1]

      Domanda 1

      You are given n tests numbered from 1, 2, 3.... N. Each test passes individually, but there are two tests which when ran together fails. You can call a function testSuite() and pass any number of test as you want. For example : Given N = 5, 1, 2, 3, 4, 5 Lets say 1 and 4 are failing tests. If you ran testSuite([1, 2, 3, 4, 5]) -> fail If you ran testSuite([1, 2, 3]) -> pass If you ran testSuite([1, 2, 4]) -> fail Likewise, testSuite([1, 4]) -> fail Can you write a algorithm (better than O(N^2) ofcourse) to find the failing tests? 2nd question: You are given a 0-indexed integer array nums and an integer k. A subarray is called equal if all of its elements are equal. Note that the empty subarray is an equal subarray. Return the length of the longest possible equal subarray after deleting at most k elements from nums. A subarray is a contiguous, possibly empty sequence of elements within an array. Example 1: Input: nums = [1,3,2,3,1,3], k = 3 Output: 3 Explanation: It's optimal to delete the elements at index 2 and index 4. After deleting them, nums becomes equal to [1, 3, 3, 3]. The longest equal subarray starts at i = 1 and ends at j = 3 with length equal to 3. It can be proven that no longer equal subarrays can be created. Example 2: Input: nums = [1,1,2,2,1,1], k = 2 Output: 4 Explanation: It's optimal to delete the elements at index 2 and index 3. After deleting them, nums becomes equal to [1, 1, 1, 1]. The array itself is an equal subarray, so the answer is 4. It can be proven that no longer equal subarrays can be created.
      1 risposta

      Altre recensioni di colloqui per Software Engineer(Internship) presso HugoSave

      Colloquio per Software Engineer(Internship)

      31 lug 2025
      Candidato anonimo a colloquio
      Hyderabad
      Nessuna offerta
      Esperienza positiva
      Colloquio nella media

      Candidatura

      Ho presentato la mia candidatura tramite un'altra fonte. La procedura ha richiesto un giorno. Ho sostenuto un colloquio presso HugoSave (Hyderabad) nel mese di giu 2025

      Colloquio

      There were 2 rounds; both were DSA focused. They were very user-friendly and will encourage you during the interview process. Both the questions from the Striver DSA sheet and from easy to medium. level.

      Domande di colloquio [1]

      Domanda 1

      first question they ask about sorting algorithms and complexity related to that then they asked me about merge sorting and said me to write the full code. In second round they asked me medium level questions from strings
      Rispondi alla domanda

      Colloquio per Software Engineer(Internship)

      24 ott 2024
      Candidato anonimo a colloquio
      Hyderabad
      Nessuna offerta
      Esperienza positiva
      Colloquio nella media

      Candidatura

      Ho presentato la mia candidatura tramite l'università. La procedura ha richiesto una settimana. Ho sostenuto un colloquio presso HugoSave (Hyderabad) nel mese di ago 2024

      Colloquio

      It was on-campus opportunity. Held in the month of August. First round was a test, 2 medium to hard level questions. Based on the code written the platform checks for any plagiarism, and out of around 40 students 2 were selected. And the next rounds were 2 technical rounds and a HR round. Both were based on medium level Leetcode questions, but a modified version and a greedy problem, followed by Projects discussion. Both rounds of half an hour each. I was not able to explain the optimal approach properly, so didn't have an HR round.

      Domande di colloquio [1]

      Domanda 1

      3 Sum closest question and all approaches, and other questions based on Greedy and Binary Search
      Rispondi alla domanda

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