In java and using math, check if a number is a palindrome.

Question

hivejin · Accepted Answer

boolean isPalindromNumber(int n) {
    if(n == null)
        return true;
    return n == reverseNumber(n);
}

long reverseNumber(int n) {
    long rev = 0;
    while(n != 0)
        rev = rev * 10 + n % 10;
        n /= 10;
    }
    return rev;
}

Anonimo · Answer

The above doesn't actually work for all cases. For example try 2020. This will solve for all possibilities:

public static boolean isPalindromeNumber(int n) {
    	int rev = 0;
    	int orig = n;
	 while(n != 0) {
	        rev = rev * 10 + n % 10;
	        n /= 10;
	  }
    	
    	if(orig % 10 == 0) {
    		rev *= 10;
    	}
    	return (orig == rev);
    }

Anonimo · Answer

How is 2020 a palindrome?

Anonimo · Answer

The point is to use math, as explicitly said.

Anonimo · Answer

Convert to string and then either (a) revers and compare or (b) using two counters compare characters from both ends until they are not equal or they meet.

Salesforce

Domanda di colloquio di Salesforce

Risposte di colloquio

Aziende seguite

Ricerche di lavoro