Ho presentato la mia candidatura tramite un selezionatore. La procedura ha richiesto 2 settimane. Ho sostenuto un colloquio presso ThousandEyes (San Francisco, CA) nel mese di lug 2017
Colloquio
It was a great process, contacted by recruiter and then talked with a HR(all is very quick and nice). The last exercise it is a bit lit longer, but you can do it.
Ho sostenuto un colloquio presso ThousandEyes (New York, NY)
Colloquio
I found the question fair but challenging. While I understood the fundamentals, my lack of experience with certain advanced techniques kept me from fully passing. I'll focus on refining these areas to improve my performance in the future. Thank you for the opportunity.
Ho presentato la mia candidatura tramite un selezionatore. La procedura ha richiesto 3 settimane. Ho sostenuto un colloquio presso ThousandEyes nel mese di giu 2022
Colloquio
Initial Leetcode - style Interview followed by on site
On site consisted of another coding round, systems design, and behavioral. I was not in the right headspace and did poorly on the first coding round. They allowed me to schedule one more coding round to "make up" for my first failing (despite passing through the initial coding round). The "make up" round was an extremely vague question with no example inputs/outputs and despite trying to communicate with the interviewer on the question, he told me another requirement of the problem which completely changed how I would have designed the solution 5 minutes before the end of the interview.
Domande di colloquio [2]
Domanda 1
Due to the NDA, I will keep it vague.
Leetcode Hard graph problem (Djikstra's but with some tweaks)
Ho presentato la mia candidatura online. Ho sostenuto un colloquio presso ThousandEyes
Colloquio
A fairly regular software engineer interview process. The first call was with the recruiter. After that, there was a technical round with one of the developers. The response time was also quick.
Domande di colloquio [1]
Domanda 1
Implement a new data structure which can do following
set(key, value)
get(key)
last()
delete(key)