Ho presentato la mia candidatura online. Ho sostenuto un colloquio presso Microsoft (Tel Aviv) nel mese di gen 2021
Colloquio
The first round includes 2 parts: first one is a codility test that has 3 problems to solve (2 of them were ridiculously easy, while the last one was super hard).
second is an interview via Skype. The recruiter was very nice and polite, asked be about projects I've done and problems I've encountered... mostly behavioral.
Domande di colloquio [1]
Domanda 1
Tell me about a time you worked on a project with somone that was hard to work with and how you managed.
Ho sostenuto un colloquio presso Microsoft (Tel Aviv)
Colloquio
I applied through their website with a referral, after a month or so they sent me a home exam, I think about a month after that i had 3 interviews in the same day, each one around 1:15 hours.
Domande di colloquio [1]
Domanda 1
implement a dictionary where you have set,get and setAll, all in O(1)
The hiring process consists of a HackerRank home exam, followed by three technical interviews covering LeetCode-style problems and system architecture. Once this is done, you will have a final HR interview.
Domande di colloquio [1]
Domanda 1
I had a technical interview where I was asked to solve the classic 'Climbing Stairs' problem (LeetCode #70), which is a dynamic programming question based on the Fibonacci sequence.
Ho presentato la mia candidatura tramite l'università. Ho sostenuto un colloquio presso Microsoft (Haifa) nel mese di giu 2026
Colloquio
The process started with an online HackerRank assessment. The main coding question involved partitioning an array of server capacities into K contiguous groups while minimizing the maximum group sum. The solution required binary search on the answer combined with a greedy validation function. The assessment focused on algorithms, problem solving, and time complexity analysis.
Domande di colloquio [1]
Domanda 1
Given an array representing server capacities and an integer K, divide the array into K contiguous groups such that the largest group sum is minimized. Return the minimum possible value of the maximum group sum.